Hill Sphere Calculator
Find how far a body's gravity holds satellites.
Result
How it is calculated
The Hill radius is rH = a × (1 − e) × (m / 3M)1/3. Here a is the semi-major axis of the orbit in kilometres, e the orbital eccentricity, m the mass of the smaller body and M the mass of the body it orbits, both in kilograms. The factor (1 − e) shrinks the radius for an elliptical orbit by using the closest approach. If eccentricity is left empty, negative or 1 or more, the tool uses 0 (a circular orbit). Axis and both masses must be positive. The result is shown in kilometres and in millions of kilometres. It is an approximation for a small body orbiting a much heavier one; stable satellite orbits sit well inside this boundary, not at its edge.
Worked example
Use Earth-like values: a = 149,600,000 km, e = 0.0167, m = 5.972e24 kg and M = 1.989e30 kg. The factor 1 − e = 0.9833 gives a closest distance of about 147,101,680 km. Next m / 3M = 5.972e24 / 5.967e30 ≈ 1.0008×10⁻⁶, whose cube root is about 0.0100028. Multiplying gives 1,471,428 km, or 1.4714 million km.
Common mistakes
- Entering the distance in astronomical units or metres; the tool expects kilometres.
- Using masses in tonnes or solar masses; both masses must be in kilograms.
- Swapping the two masses so that the heavier body is entered as m.
- Typing eccentricity as a percentage (1.67), which is 1 or more and is silently replaced by 0.
- Treating the Hill radius as the limit for a stable orbit; real stable orbits stay at a fraction of it.
About this calculator
The Hill sphere (or Roche sphere) is the region around a celestial body — a planet orbiting a star, or a moon orbiting a planet — within which its own gravity dominates over the pull of the larger body it orbits, so that it can hold onto satellites. It's approximated by r ≈ a·(m / 3M)^(1/3), where a is the orbital distance between the smaller body (mass m) and the larger one (mass M).
Astronomers use the Hill sphere to determine whether a planet's candidate moon can remain gravitationally bound, to set the outer stability limit for exoplanet moons ("exomoons") in habitability studies, and to explain why moons far from a planet (like an outer irregular satellite) are more easily stripped away by the Sun's gravity. Earth's Hill sphere, for comparison, extends to about 1.5 million km — well beyond the Moon's orbit, which is why the Moon remains stably bound to Earth rather than the Sun.
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